Alexey Medvedev

web developer

Contacts

City: Tambov

telegram: @spiritlm

discord: spiritlm#6028

Language

A1 - I read and translate with a dictionary

Russian: Native

Skills

Basic Object-oriented programming skills (Java, Python).

Education

Higher education in the specialty "Organization and information security technologies"

About me

At the moment I work as a network-system administrator in a large gas industry company. In the near future I plan to change my specialty in the direction of backend or frontend development. I learn quickly and assimilate new information.

Sample code

import java.text.DecimalFormat;
import java.util.Scanner;
    public class Solving {
        public static void main(String[] args) {
                Diskriminant Diskr = new Diskriminant();
                    
                Scanner in = new Scanner(System.in);
                System.out.print("Введите а: ");
                double a = in.nextDouble();
                    
                System.out.print("Введите b: ");
                double b = in.nextDouble();
                    
                System.out.print("Введите c: ");
                double c = in.nextDouble();   
                in.close();
                    
                    double d = (Math.pow(b, 2)) - (4 * a * c);
                    
                    DecimalFormat decimalFormat = new DecimalFormat("#.###");
                        String result = decimalFormat.format(d);
                        System.out.println(("Дискриминант равен: " + result));
                    
                if (d > 0) {
                    double x1 = (-b + Math.sqrt(d) / (2 * a));
                        String resultX1 = decimalFormat.format(x1);
                        System.out.println(("x1 = : " + resultX1));
                    
                        double x2 = (-b - Math.sqrt(d) / (2 * a));
                            String resultX2 = decimalFormat.format(x2);
                            System.out.println(("x2 = : " + resultX2));
                    
                } else if (d == 0) {
                    double x1 = (-b + Math.sqrt(d) / (2 * a));
                    System.out.println("x1 = " + x1);
                }
                    else {
                        System.out.println("Корней нет");
                }
            }
        }